10y-5(1+4)=3(2y-2)=20

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Solution for 10y-5(1+4)=3(2y-2)=20 equation: 



10y-5(1+4)=3(2y-2)=20

We move all terms to the left:

10y-5(1+4)-(3(2y-2))=0

We add all the numbers together, and all the variables

10y-(3(2y-2))-55=0



We calculate terms in parentheses: -(3(2y-2)), so:

3(2y-2)

We multiply parentheses

6y-6

Back to the equation:

-(6y-6)



We get rid of parentheses

10y-6y+6-55=0

We add all the numbers together, and all the variables

4y-49=0

We move all terms containing y to the left, all other terms to the right

4y=49

y=49/4

y=12+1/4

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