10y-5(1+y)=3(y-2)-20

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Solution for 10y-5(1+y)=3(y-2)-20 equation:


Simplifying
10y + -5(1 + y) = 3(y + -2) + -20
10y + (1 * -5 + y * -5) = 3(y + -2) + -20
10y + (-5 + -5y) = 3(y + -2) + -20

Reorder the terms:
-5 + 10y + -5y = 3(y + -2) + -20

Combine like terms: 10y + -5y = 5y
-5 + 5y = 3(y + -2) + -20

Reorder the terms:
-5 + 5y = 3(-2 + y) + -20
-5 + 5y = (-2 * 3 + y * 3) + -20
-5 + 5y = (-6 + 3y) + -20

Reorder the terms:
-5 + 5y = -6 + -20 + 3y

Combine like terms: -6 + -20 = -26
-5 + 5y = -26 + 3y

Solving
-5 + 5y = -26 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-5 + 5y + -3y = -26 + 3y + -3y

Combine like terms: 5y + -3y = 2y
-5 + 2y = -26 + 3y + -3y

Combine like terms: 3y + -3y = 0
-5 + 2y = -26 + 0
-5 + 2y = -26

Add '5' to each side of the equation.
-5 + 5 + 2y = -26 + 5

Combine like terms: -5 + 5 = 0
0 + 2y = -26 + 5
2y = -26 + 5

Combine like terms: -26 + 5 = -21
2y = -21

Divide each side by '2'.
y = -10.5

Simplifying
y = -10.5

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