10y-5(1-y)=3(2y-2)-20

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Solution for 10y-5(1-y)=3(2y-2)-20 equation: 



10y-5(1-y)=3(2y-2)-20

We move all terms to the left:

10y-5(1-y)-(3(2y-2)-20)=0

We add all the numbers together, and all the variables

10y-5(-1y+1)-(3(2y-2)-20)=0

We multiply parentheses

10y+5y-(3(2y-2)-20)-5=0



We calculate terms in parentheses: -(3(2y-2)-20), so:

3(2y-2)-20

We multiply parentheses

6y-6-20

We add all the numbers together, and all the variables

6y-26

Back to the equation:

-(6y-26)



We add all the numbers together, and all the variables

15y-(6y-26)-5=0

We get rid of parentheses

15y-6y+26-5=0

We add all the numbers together, and all the variables

9y+21=0

We move all terms containing y to the left, all other terms to the right

9y=-21

y=-21/9

y=-2+1/3

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