10y-5(2+y)=3(y-2)-20

Solution for 10y-5(2+y)=3(y-2)-20 equation:

10y-5(2+y)=3(y-2)-20

We move all terms to the left:

10y-5(2+y)-(3(y-2)-20)=0

We add all the numbers together, and all the variables

10y-5(y+2)-(3(y-2)-20)=0

We multiply parentheses

10y-5y-(3(y-2)-20)-10=0


We calculate terms in parentheses: -(3(y-2)-20), so:

3(y-2)-20

We multiply parentheses

3y-6-20

We add all the numbers together, and all the variables

3y-26

Back to the equation:

-(3y-26)


We add all the numbers together, and all the variables

5y-(3y-26)-10=0

We get rid of parentheses

5y-3y+26-10=0

We add all the numbers together, and all the variables

2y+16=0

We move all terms containing y to the left, all other terms to the right

2y=-16

y=-16/2

y=-8