10y-5+2y=-21+3(y-2)

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Solution for 10y-5+2y=-21+3(y-2) equation: 



10y-5+2y=-21+3(y-2)

We move all terms to the left:

10y-5+2y-(-21+3(y-2))=0

We add all the numbers together, and all the variables

12y-(-21+3(y-2))-5=0



We calculate terms in parentheses: -(-21+3(y-2)), so:

-21+3(y-2)

determiningTheFunctionDomain
3(y-2)-21

We multiply parentheses

3y-6-21

We add all the numbers together, and all the variables

3y-27

Back to the equation:

-(3y-27)



We get rid of parentheses

12y-3y+27-5=0

We add all the numbers together, and all the variables

9y+22=0

We move all terms containing y to the left, all other terms to the right

9y=-22

y=-22/9

y=-2+4/9

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