10y/9+1/3=(2y-1)/9

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Solution for 10y/9+1/3=(2y-1)/9 equation: 



10y/9+1/3=(2y-1)/9

We move all terms to the left:

10y/9+1/3-((2y-1)/9)=0

We calculate fractions


30y/()+(-((2y-1)*3)/()+()/()=0



We calculate terms in parentheses: +(-((2y-1)*3)/()+()/(), so:

-((2y-1)*3)/()+()/(

We add all the numbers together, and all the variables

-((2y-1)*3)/()+1

We multiply all the terms by the denominator


-((2y-1)*3)+1*()



We calculate terms in parentheses: -((2y-1)*3), so:

(2y-1)*3

We multiply parentheses

6y-3

Back to the equation:

-(6y-3)



We add all the numbers together, and all the variables

-(6y-3)

We get rid of parentheses

-6y+3

Back to the equation:

+(-6y+3)



We get rid of parentheses

30y/()-6y+3=0

We multiply all the terms by the denominator


30y-6y*()+3*()=0

We add all the numbers together, and all the variables

30y-6y*()=0

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