10y2+12y=16

Solution for 10y2+12y=16 equation:

10y^2+12y=16

We move all terms to the left:

10y^2+12y-(16)=0

a = 10; b = 12; c = -16;
Δ = b2-4ac
Δ = 122-4·10·(-16)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-28}{2*10}=\frac{-40}{20}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+28}{2*10}=\frac{16}{20}
=4/5
$