10y2+2=9y

Solution for 10y2+2=9y equation:

10y^2+2=9y

We move all terms to the left:

10y^2+2-(9y)=0

a = 10; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·10·2
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-1}{2*10}=\frac{8}{20}
=2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+1}{2*10}=\frac{10}{20}
=1/2
$