10y2+57y+35=0

Solution for 10y2+57y+35=0 equation:

10y^2+57y+35=0

a = 10; b = 57; c = +35;
Δ = b2-4ac
Δ = 572-4·10·35
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-43}{2*10}=\frac{-100}{20}
=-5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+43}{2*10}=\frac{-14}{20}
=-7/10
$