10y2+7y-45=0

Solution for 10y2+7y-45=0 equation:

10y^2+7y-45=0

a = 10; b = 7; c = -45;
Δ = b2-4ac
Δ = 72-4·10·(-45)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-43}{2*10}=\frac{-50}{20}
=-2+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+43}{2*10}=\frac{36}{20}
=1+4/5
$