10z+150=3z+30

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Solution for 10z+150=3z+30 equation: 



10z+150=3z+30

We move all terms to the left:

10z+150-(3z+30)=0

We get rid of parentheses

10z-3z-30+150=0

We add all the numbers together, and all the variables

7z+120=0

We move all terms containing z to the left, all other terms to the right

7z=-120

z=-120/7

z=-17+1/7

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