10z+3(2-z)=5(z+2)-4

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Solution for 10z+3(2-z)=5(z+2)-4 equation: 



10z+3(2-z)=5(z+2)-4

We move all terms to the left:

10z+3(2-z)-(5(z+2)-4)=0

We add all the numbers together, and all the variables

10z+3(-1z+2)-(5(z+2)-4)=0

We multiply parentheses

10z-3z-(5(z+2)-4)+6=0



We calculate terms in parentheses: -(5(z+2)-4), so:

5(z+2)-4

We multiply parentheses

5z+10-4

We add all the numbers together, and all the variables

5z+6

Back to the equation:

-(5z+6)



We add all the numbers together, and all the variables

7z-(5z+6)+6=0

We get rid of parentheses

7z-5z-6+6=0

We add all the numbers together, and all the variables

2z=0

z=0/2

z=0

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