10z+4=295z+80-12

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Solution for 10z+4=295z+80-12 equation: 



10z+4=295z+80-12

We move all terms to the left:

10z+4-(295z+80-12)=0

We add all the numbers together, and all the variables

10z-(295z+68)+4=0

We get rid of parentheses

10z-295z-68+4=0

We add all the numbers together, and all the variables

-285z-64=0

We move all terms containing z to the left, all other terms to the right

-285z=64

z=64/-285

z=-64/285

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