10z-22=3(3z+11)-z

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Solution for 10z-22=3(3z+11)-z equation: 



10z-22=3(3z+11)-z

We move all terms to the left:

10z-22-(3(3z+11)-z)=0



We calculate terms in parentheses: -(3(3z+11)-z), so:

3(3z+11)-z

We add all the numbers together, and all the variables

-1z+3(3z+11)

We multiply parentheses

-1z+9z+33

We add all the numbers together, and all the variables

8z+33

Back to the equation:

-(8z+33)



We get rid of parentheses

10z-8z-33-22=0

We add all the numbers together, and all the variables

2z-55=0

We move all terms containing z to the left, all other terms to the right

2z=55

z=55/2

z=27+1/2

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