10z-6(z-3)=3(z+2)

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Solution for 10z-6(z-3)=3(z+2) equation: 



10z-6(z-3)=3(z+2)

We move all terms to the left:

10z-6(z-3)-(3(z+2))=0

We multiply parentheses

10z-6z-(3(z+2))+18=0



We calculate terms in parentheses: -(3(z+2)), so:

3(z+2)

We multiply parentheses

3z+6

Back to the equation:

-(3z+6)



We add all the numbers together, and all the variables

4z-(3z+6)+18=0

We get rid of parentheses

4z-3z-6+18=0

We add all the numbers together, and all the variables

z+12=0

We move all terms containing z to the left, all other terms to the right

z=-12

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