10z-8-(6+3z)=-28

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Solution for 10z-8-(6+3z)=-28 equation: 



10z-8-(6+3z)=-28

We move all terms to the left:

10z-8-(6+3z)-(-28)=0

We add all the numbers together, and all the variables

10z-(3z+6)-8-(-28)=0

We add all the numbers together, and all the variables

10z-(3z+6)+20=0

We get rid of parentheses

10z-3z-6+20=0

We add all the numbers together, and all the variables

7z+14=0

We move all terms containing z to the left, all other terms to the right

7z=-14

z=-14/7

z=-2

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