11(-3x-11)+5=-8(x-4)+152

Solution for 11(-3x-11)+5=-8(x-4)+152 equation:

11(-3x-11)+5=-8(x-4)+152

We move all terms to the left:

11(-3x-11)+5-(-8(x-4)+152)=0

We multiply parentheses

-33x-(-8(x-4)+152)-121+5=0


We calculate terms in parentheses: -(-8(x-4)+152), so:

-8(x-4)+152

We multiply parentheses

-8x+32+152

We add all the numbers together, and all the variables

-8x+184

Back to the equation:

-(-8x+184)


We add all the numbers together, and all the variables

-33x-(-8x+184)-116=0

We get rid of parentheses

-33x+8x-184-116=0

We add all the numbers together, and all the variables

-25x-300=0

We move all terms containing x to the left, all other terms to the right

-25x=300

x=300/-25

x=-12