11(-8+4b)=-11(-2b-4)

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Solution for 11(-8+4b)=-11(-2b-4) equation:



11(-8+4b)=-11(-2b-4)
We move all terms to the left:
11(-8+4b)-(-11(-2b-4))=0
We add all the numbers together, and all the variables
11(4b-8)-(-11(-2b-4))=0
We multiply parentheses
44b-(-11(-2b-4))-88=0
We calculate terms in parentheses: -(-11(-2b-4)), so:
-11(-2b-4)
We multiply parentheses
22b+44
Back to the equation:
-(22b+44)
We get rid of parentheses
44b-22b-44-88=0
We add all the numbers together, and all the variables
22b-132=0
We move all terms containing b to the left, all other terms to the right
22b=132
b=132/22
b=6

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