11(-8+4b)=-11(-2b-4)

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Solution for 11(-8+4b)=-11(-2b-4) equation: 



11(-8+4b)=-11(-2b-4)

We move all terms to the left:

11(-8+4b)-(-11(-2b-4))=0

We add all the numbers together, and all the variables

11(4b-8)-(-11(-2b-4))=0

We multiply parentheses

44b-(-11(-2b-4))-88=0



We calculate terms in parentheses: -(-11(-2b-4)), so:

-11(-2b-4)

We multiply parentheses

22b+44

Back to the equation:

-(22b+44)



We get rid of parentheses

44b-22b-44-88=0

We add all the numbers together, and all the variables

22b-132=0

We move all terms containing b to the left, all other terms to the right

22b=132

b=132/22

b=6

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