11(1+3x)=7(8+6x)

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Solution for 11(1+3x)=7(8+6x) equation: 



11(1+3x)=7(8+6x)

We move all terms to the left:

11(1+3x)-(7(8+6x))=0

We add all the numbers together, and all the variables

11(3x+1)-(7(6x+8))=0

We multiply parentheses

33x-(7(6x+8))+11=0



We calculate terms in parentheses: -(7(6x+8)), so:

7(6x+8)

We multiply parentheses

42x+56

Back to the equation:

-(42x+56)



We get rid of parentheses

33x-42x-56+11=0

We add all the numbers together, and all the variables

-9x-45=0

We move all terms containing x to the left, all other terms to the right

-9x=45

x=45/-9

x=-5

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