11(1-y)=2(y+5)

Solution for 11(1-y)=2(y+5) equation:

11(1-y)=2(y+5)

We move all terms to the left:

11(1-y)-(2(y+5))=0

We add all the numbers together, and all the variables

11(-1y+1)-(2(y+5))=0

We multiply parentheses

-11y-(2(y+5))+11=0


We calculate terms in parentheses: -(2(y+5)), so:

2(y+5)

We multiply parentheses

2y+10

Back to the equation:

-(2y+10)


We get rid of parentheses

-11y-2y-10+11=0

We add all the numbers together, and all the variables

-13y+1=0

We move all terms containing y to the left, all other terms to the right

-13y=-1

y=-1/-13

y=1/13