11(10b-7)=11(4b-1)

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Solution for 11(10b-7)=11(4b-1) equation: 



11(10b-7)=11(4b-1)

We move all terms to the left:

11(10b-7)-(11(4b-1))=0

We multiply parentheses

110b-(11(4b-1))-77=0



We calculate terms in parentheses: -(11(4b-1)), so:

11(4b-1)

We multiply parentheses

44b-11

Back to the equation:

-(44b-11)



We get rid of parentheses

110b-44b+11-77=0

We add all the numbers together, and all the variables

66b-66=0

We move all terms containing b to the left, all other terms to the right

66b=66

b=66/66

b=1

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