11(2a-2)+2a=4(1-6a)

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Solution for 11(2a-2)+2a=4(1-6a) equation: 



11(2a-2)+2a=4(1-6a)

We move all terms to the left:

11(2a-2)+2a-(4(1-6a))=0

We add all the numbers together, and all the variables

11(2a-2)+2a-(4(-6a+1))=0

We add all the numbers together, and all the variables

2a+11(2a-2)-(4(-6a+1))=0

We multiply parentheses

2a+22a-(4(-6a+1))-22=0



We calculate terms in parentheses: -(4(-6a+1)), so:

4(-6a+1)

We multiply parentheses

-24a+4

Back to the equation:

-(-24a+4)



We add all the numbers together, and all the variables

24a-(-24a+4)-22=0

We get rid of parentheses

24a+24a-4-22=0

We add all the numbers together, and all the variables

48a-26=0

We move all terms containing a to the left, all other terms to the right

48a=26

a=26/48

a=13/24

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