11(2b+3)+15=17(b-5)

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Solution for 11(2b+3)+15=17(b-5) equation: 



11(2b+3)+15=17(b-5)

We move all terms to the left:

11(2b+3)+15-(17(b-5))=0

We multiply parentheses

22b-(17(b-5))+33+15=0



We calculate terms in parentheses: -(17(b-5)), so:

17(b-5)

We multiply parentheses

17b-85

Back to the equation:

-(17b-85)



We add all the numbers together, and all the variables

22b-(17b-85)+48=0

We get rid of parentheses

22b-17b+85+48=0

We add all the numbers together, and all the variables

5b+133=0

We move all terms containing b to the left, all other terms to the right

5b=-133

b=-133/5

b=-26+3/5

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