11(2b+3)=-6b-51

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Solution for 11(2b+3)=-6b-51 equation: 



11(2b+3)=-6b-51

We move all terms to the left:

11(2b+3)-(-6b-51)=0

We multiply parentheses

22b-(-6b-51)+33=0

We get rid of parentheses

22b+6b+51+33=0

We add all the numbers together, and all the variables

28b+84=0

We move all terms containing b to the left, all other terms to the right

28b=-84

b=-84/28

b=-3

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