11(2b+3)=-6b-51

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Solution for 11(2b+3)=-6b-51 equation:



11(2b+3)=-6b-51
We move all terms to the left:
11(2b+3)-(-6b-51)=0
We multiply parentheses
22b-(-6b-51)+33=0
We get rid of parentheses
22b+6b+51+33=0
We add all the numbers together, and all the variables
28b+84=0
We move all terms containing b to the left, all other terms to the right
28b=-84
b=-84/28
b=-3

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