11(2t+2)-6=4t+4(3t-2)

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Solution for 11(2t+2)-6=4t+4(3t-2) equation: 



11(2t+2)-6=4t+4(3t-2)

We move all terms to the left:

11(2t+2)-6-(4t+4(3t-2))=0

We multiply parentheses

22t-(4t+4(3t-2))+22-6=0



We calculate terms in parentheses: -(4t+4(3t-2)), so:

4t+4(3t-2)

We multiply parentheses

4t+12t-8

We add all the numbers together, and all the variables

16t-8

Back to the equation:

-(16t-8)



We add all the numbers together, and all the variables

22t-(16t-8)+16=0

We get rid of parentheses

22t-16t+8+16=0

We add all the numbers together, and all the variables

6t+24=0

We move all terms containing t to the left, all other terms to the right

6t=-24

t=-24/6

t=-4

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