11(2x+40)=7(2/11x)

Solution for 11(2x+40)=7(2/11x) equation:

11(2x+40)=7(2/11x)

We move all terms to the left:

11(2x+40)-(7(2/11x))=0


Domain of the equation: 11x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

11(2x+40)-(7(+2/11x))=0

We multiply parentheses

22x-(7(+2/11x))+440=0

We multiply all the terms by the denominator


22x*11x))-(7(+440*11x))+2=0

Wy multiply elements

242x^2+4840x=0

a = 242; b = 4840; c = 0;
Δ = b2-4ac
Δ = 48402-4·242·0
Δ = 23425600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23425600}=4840$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4840)-4840}{2*242}=\frac{-9680}{484}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4840)+4840}{2*242}=\frac{0}{484}
=0
$