11(2x-1)=8(2x+1)+29

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Solution for 11(2x-1)=8(2x+1)+29 equation: 



11(2x-1)=8(2x+1)+29

We move all terms to the left:

11(2x-1)-(8(2x+1)+29)=0

We multiply parentheses

22x-(8(2x+1)+29)-11=0



We calculate terms in parentheses: -(8(2x+1)+29), so:

8(2x+1)+29

We multiply parentheses

16x+8+29

We add all the numbers together, and all the variables

16x+37

Back to the equation:

-(16x+37)



We get rid of parentheses

22x-16x-37-11=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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