11(2x-1)=8(2x+1)+35

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Solution for 11(2x-1)=8(2x+1)+35 equation: 



11(2x-1)=8(2x+1)+35

We move all terms to the left:

11(2x-1)-(8(2x+1)+35)=0

We multiply parentheses

22x-(8(2x+1)+35)-11=0



We calculate terms in parentheses: -(8(2x+1)+35), so:

8(2x+1)+35

We multiply parentheses

16x+8+35

We add all the numbers together, and all the variables

16x+43

Back to the equation:

-(16x+43)



We get rid of parentheses

22x-16x-43-11=0

We add all the numbers together, and all the variables

6x-54=0

We move all terms containing x to the left, all other terms to the right

6x=54

x=54/6

x=9

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