11(2x-3)=(2x+2)+5

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Solution for 11(2x-3)=(2x+2)+5 equation: 



11(2x-3)=(2x+2)+5

We move all terms to the left:

11(2x-3)-((2x+2)+5)=0

We multiply parentheses

22x-((2x+2)+5)-33=0



We calculate terms in parentheses: -((2x+2)+5), so:

(2x+2)+5

We get rid of parentheses

2x+2+5

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We get rid of parentheses

22x-2x-7-33=0

We add all the numbers together, and all the variables

20x-40=0

We move all terms containing x to the left, all other terms to the right

20x=40

x=40/20

x=2

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