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11(2x-3)=5(2x+2)+5
We move all terms to the left:
11(2x-3)-(5(2x+2)+5)=0
We multiply parentheses
22x-(5(2x+2)+5)-33=0
We calculate terms in parentheses: -(5(2x+2)+5), so:We get rid of parentheses
5(2x+2)+5
We multiply parentheses
10x+10+5
We add all the numbers together, and all the variables
10x+15
Back to the equation:
-(10x+15)
22x-10x-15-33=0
We add all the numbers together, and all the variables
12x-48=0
We move all terms containing x to the left, all other terms to the right
12x=48
x=48/12
x=4
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