11(2x-3)=5(2x+2)5

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Solution for 11(2x-3)=5(2x+2)5 equation: 



11(2x-3)=5(2x+2)5

We move all terms to the left:

11(2x-3)-(5(2x+2)5)=0

We multiply parentheses

22x-(5(2x+2)5)-33=0



We calculate terms in parentheses: -(5(2x+2)5), so:

5(2x+2)5

We multiply parentheses

50x+50

Back to the equation:

-(50x+50)



We get rid of parentheses

22x-50x-50-33=0

We add all the numbers together, and all the variables

-28x-83=0

We move all terms containing x to the left, all other terms to the right

-28x=83

x=83/-28

x=-2+27/28

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