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11(2x-3)=5(2x+2+5)
We move all terms to the left:
11(2x-3)-(5(2x+2+5))=0
We add all the numbers together, and all the variables
11(2x-3)-(5(2x+7))=0
We multiply parentheses
22x-(5(2x+7))-33=0
We calculate terms in parentheses: -(5(2x+7)), so:We get rid of parentheses
5(2x+7)
We multiply parentheses
10x+35
Back to the equation:
-(10x+35)
22x-10x-35-33=0
We add all the numbers together, and all the variables
12x-68=0
We move all terms containing x to the left, all other terms to the right
12x=68
x=68/12
x=5+2/3
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