11(2x-8)=7(3+5x)

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Solution for 11(2x-8)=7(3+5x) equation: 



11(2x-8)=7(3+5x)

We move all terms to the left:

11(2x-8)-(7(3+5x))=0

We add all the numbers together, and all the variables

11(2x-8)-(7(5x+3))=0

We multiply parentheses

22x-(7(5x+3))-88=0



We calculate terms in parentheses: -(7(5x+3)), so:

7(5x+3)

We multiply parentheses

35x+21

Back to the equation:

-(35x+21)



We get rid of parentheses

22x-35x-21-88=0

We add all the numbers together, and all the variables

-13x-109=0

We move all terms containing x to the left, all other terms to the right

-13x=109

x=109/-13

x=-8+5/13

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