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11(3-x)=10(x-6/3)
We move all terms to the left:
11(3-x)-(10(x-6/3))=0
We add all the numbers together, and all the variables
11(-1x+3)-(10(x-2))=0
We multiply parentheses
-11x-(10(x-2))+33=0
We calculate terms in parentheses: -(10(x-2)), so:We get rid of parentheses
10(x-2)
We multiply parentheses
10x-20
Back to the equation:
-(10x-20)
-11x-10x+20+33=0
We add all the numbers together, and all the variables
-21x+53=0
We move all terms containing x to the left, all other terms to the right
-21x=-53
x=-53/-21
x=2+11/21
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