11(3a+2a)-14=27-5(3-3a)

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Solution for 11(3a+2a)-14=27-5(3-3a) equation: 



11(3a+2a)-14=27-5(3-3a)

We move all terms to the left:

11(3a+2a)-14-(27-5(3-3a))=0

We add all the numbers together, and all the variables

11(+5a)-(27-5(-3a+3))-14=0

We multiply parentheses

55a-(27-5(-3a+3))-14=0



We calculate terms in parentheses: -(27-5(-3a+3)), so:

27-5(-3a+3)

determiningTheFunctionDomain
-5(-3a+3)+27

We multiply parentheses

15a-15+27

We add all the numbers together, and all the variables

15a+12

Back to the equation:

-(15a+12)



We get rid of parentheses

55a-15a-12-14=0

We add all the numbers together, and all the variables

40a-26=0

We move all terms containing a to the left, all other terms to the right

40a=26

a=26/40

a=13/20

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