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11(3x+1)=11(2x+7)
We move all terms to the left:
11(3x+1)-(11(2x+7))=0
We multiply parentheses
33x-(11(2x+7))+11=0
We calculate terms in parentheses: -(11(2x+7)), so:We get rid of parentheses
11(2x+7)
We multiply parentheses
22x+77
Back to the equation:
-(22x+77)
33x-22x-77+11=0
We add all the numbers together, and all the variables
11x-66=0
We move all terms containing x to the left, all other terms to the right
11x=66
x=66/11
x=6
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