11(3x+7)=13(8x-5)=x

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Solution for 11(3x+7)=13(8x-5)=x equation: 



11(3x+7)=13(8x-5)=x

We move all terms to the left:

11(3x+7)-(13(8x-5))=0

We multiply parentheses

33x-(13(8x-5))+77=0



We calculate terms in parentheses: -(13(8x-5)), so:

13(8x-5)

We multiply parentheses

104x-65

Back to the equation:

-(104x-65)



We get rid of parentheses

33x-104x+65+77=0

We add all the numbers together, and all the variables

-71x+142=0

We move all terms containing x to the left, all other terms to the right

-71x=-142

x=-142/-71

x=+2

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