11(6.40+4.80+f)=128.15

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Solution for 11(6.40+4.80+f)=128.15 equation: 



11(6.40+4.80+f)=128.15

We move all terms to the left:

11(6.40+4.80+f)-(128.15)=0

We add all the numbers together, and all the variables

11(f+11.2)-(128.15)=0

We add all the numbers together, and all the variables

11(f+11.2)-128.15=0

We multiply parentheses

11f+123.2-128.15=0

We add all the numbers together, and all the variables

11f-4.95=0

We move all terms containing f to the left, all other terms to the right

11f=4.95

f=4.95/11

f=2.5384615384615/5.6410256410256

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