11(a+3)+12=10a-11

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Solution for 11(a+3)+12=10a-11 equation: 



11(a+3)+12=10a-11

We move all terms to the left:

11(a+3)+12-(10a-11)=0

We multiply parentheses

11a-(10a-11)+33+12=0

We get rid of parentheses

11a-10a+11+33+12=0

We add all the numbers together, and all the variables

a+56=0

We move all terms containing a to the left, all other terms to the right

a=-56

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