11(b+18)-6(2b+1)=4(-b+9)+b

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Solution for 11(b+18)-6(2b+1)=4(-b+9)+b equation:



11(b+18)-6(2b+1)=4(-b+9)+b
We move all terms to the left:
11(b+18)-6(2b+1)-(4(-b+9)+b)=0
We add all the numbers together, and all the variables
11(b+18)-6(2b+1)-(4(-1b+9)+b)=0
We multiply parentheses
11b-12b-(4(-1b+9)+b)+198-6=0
We calculate terms in parentheses: -(4(-1b+9)+b), so:
4(-1b+9)+b
We add all the numbers together, and all the variables
b+4(-1b+9)
We multiply parentheses
b-4b+36
We add all the numbers together, and all the variables
-3b+36
Back to the equation:
-(-3b+36)
We add all the numbers together, and all the variables
-1b-(-3b+36)+192=0
We get rid of parentheses
-1b+3b-36+192=0
We add all the numbers together, and all the variables
2b+156=0
We move all terms containing b to the left, all other terms to the right
2b=-156
b=-156/2
b=-78

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