11(b+18)-6(2b+1)=4(-b+9)+b

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Solution for 11(b+18)-6(2b+1)=4(-b+9)+b equation: 



11(b+18)-6(2b+1)=4(-b+9)+b

We move all terms to the left:

11(b+18)-6(2b+1)-(4(-b+9)+b)=0

We add all the numbers together, and all the variables

11(b+18)-6(2b+1)-(4(-1b+9)+b)=0

We multiply parentheses

11b-12b-(4(-1b+9)+b)+198-6=0



We calculate terms in parentheses: -(4(-1b+9)+b), so:

4(-1b+9)+b

We add all the numbers together, and all the variables

b+4(-1b+9)

We multiply parentheses

b-4b+36

We add all the numbers together, and all the variables

-3b+36

Back to the equation:

-(-3b+36)



We add all the numbers together, and all the variables

-1b-(-3b+36)+192=0

We get rid of parentheses

-1b+3b-36+192=0

We add all the numbers together, and all the variables

2b+156=0

We move all terms containing b to the left, all other terms to the right

2b=-156

b=-156/2

b=-78

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