11(b+18)-6(2b+1)=4(b+9)

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Solution for 11(b+18)-6(2b+1)=4(b+9) equation: 



11(b+18)-6(2b+1)=4(b+9)

We move all terms to the left:

11(b+18)-6(2b+1)-(4(b+9))=0

We multiply parentheses

11b-12b-(4(b+9))+198-6=0



We calculate terms in parentheses: -(4(b+9)), so:

4(b+9)

We multiply parentheses

4b+36

Back to the equation:

-(4b+36)



We add all the numbers together, and all the variables

-1b-(4b+36)+192=0

We get rid of parentheses

-1b-4b-36+192=0

We add all the numbers together, and all the variables

-5b+156=0

We move all terms containing b to the left, all other terms to the right

-5b=-156

b=-156/-5

b=31+1/5

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