11(b+2)=(-10+3b)

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Solution for 11(b+2)=(-10+3b) equation: 



11(b+2)=(-10+3b)

We move all terms to the left:

11(b+2)-((-10+3b))=0

We add all the numbers together, and all the variables

11(b+2)-((3b-10))=0

We multiply parentheses

11b-((3b-10))+22=0



We calculate terms in parentheses: -((3b-10)), so:

(3b-10)

We get rid of parentheses

3b-10

Back to the equation:

-(3b-10)



We get rid of parentheses

11b-3b+10+22=0

We add all the numbers together, and all the variables

8b+32=0

We move all terms containing b to the left, all other terms to the right

8b=-32

b=-32/8

b=-4

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