11(b-18)-6(2b+1)=4(-b+9)

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Solution for 11(b-18)-6(2b+1)=4(-b+9) equation: 



11(b-18)-6(2b+1)=4(-b+9)

We move all terms to the left:

11(b-18)-6(2b+1)-(4(-b+9))=0

We add all the numbers together, and all the variables

11(b-18)-6(2b+1)-(4(-1b+9))=0

We multiply parentheses

11b-12b-(4(-1b+9))-198-6=0



We calculate terms in parentheses: -(4(-1b+9)), so:

4(-1b+9)

We multiply parentheses

-4b+36

Back to the equation:

-(-4b+36)



We add all the numbers together, and all the variables

-1b-(-4b+36)-204=0

We get rid of parentheses

-1b+4b-36-204=0

We add all the numbers together, and all the variables

3b-240=0

We move all terms containing b to the left, all other terms to the right

3b=240

b=240/3

b=80

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