11(c-1)-15=2(2c+7)+9

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Solution for 11(c-1)-15=2(2c+7)+9 equation: 



11(c-1)-15=2(2c+7)+9

We move all terms to the left:

11(c-1)-15-(2(2c+7)+9)=0

We multiply parentheses

11c-(2(2c+7)+9)-11-15=0



We calculate terms in parentheses: -(2(2c+7)+9), so:

2(2c+7)+9

We multiply parentheses

4c+14+9

We add all the numbers together, and all the variables

4c+23

Back to the equation:

-(4c+23)



We add all the numbers together, and all the variables

11c-(4c+23)-26=0

We get rid of parentheses

11c-4c-23-26=0

We add all the numbers together, and all the variables

7c-49=0

We move all terms containing c to the left, all other terms to the right

7c=49

c=49/7

c=7

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