11(c-2)+5=3+c-20

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Solution for 11(c-2)+5=3+c-20 equation:



11(c-2)+5=3+c-20
We move all terms to the left:
11(c-2)+5-(3+c-20)=0
We add all the numbers together, and all the variables
11(c-2)-(c-17)+5=0
We multiply parentheses
11c-(c-17)-22+5=0
We get rid of parentheses
11c-c+17-22+5=0
We add all the numbers together, and all the variables
10c=0
c=0/10
c=0

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