11(c-2)+5=4+c-21

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Solution for 11(c-2)+5=4+c-21 equation: 


Simplifying
11(c + -2) + 5 = 4 + c + -21

Reorder the terms:
11(-2 + c) + 5 = 4 + c + -21
(-2 * 11 + c * 11) + 5 = 4 + c + -21
(-22 + 11c) + 5 = 4 + c + -21

Reorder the terms:
-22 + 5 + 11c = 4 + c + -21

Combine like terms: -22 + 5 = -17
-17 + 11c = 4 + c + -21

Reorder the terms:
-17 + 11c = 4 + -21 + c

Combine like terms: 4 + -21 = -17
-17 + 11c = -17 + c

Add '17' to each side of the equation.
-17 + 17 + 11c = -17 + 17 + c

Combine like terms: -17 + 17 = 0
0 + 11c = -17 + 17 + c
11c = -17 + 17 + c

Combine like terms: -17 + 17 = 0
11c = 0 + c
11c = c

Solving
11c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
11c + -1c = c + -1c

Combine like terms: 11c + -1c = 10c
10c = c + -1c

Combine like terms: c + -1c = 0
10c = 0

Divide each side by '10'.
c = 0.0

Simplifying
c = 0.0

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