11(c-2)+6=5+c-21

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Solution for 11(c-2)+6=5+c-21 equation: 



11(c-2)+6=5+c-21

We move all terms to the left:

11(c-2)+6-(5+c-21)=0

We add all the numbers together, and all the variables

11(c-2)-(c-16)+6=0

We multiply parentheses

11c-(c-16)-22+6=0

We get rid of parentheses

11c-c+16-22+6=0

We add all the numbers together, and all the variables

10c=0

c=0/10

c=0

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