11(c-5)+6=4+c-53

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Solution for 11(c-5)+6=4+c-53 equation: 



11(c-5)+6=4+c-53

We move all terms to the left:

11(c-5)+6-(4+c-53)=0

We add all the numbers together, and all the variables

11(c-5)-(c-49)+6=0

We multiply parentheses

11c-(c-49)-55+6=0

We get rid of parentheses

11c-c+49-55+6=0

We add all the numbers together, and all the variables

10c=0

c=0/10

c=0

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