11(j+2)-7j=3(2j+5)+1

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Solution for 11(j+2)-7j=3(2j+5)+1 equation: 


Simplifying
11(j + 2) + -7j = 3(2j + 5) + 1

Reorder the terms:
11(2 + j) + -7j = 3(2j + 5) + 1
(2 * 11 + j * 11) + -7j = 3(2j + 5) + 1
(22 + 11j) + -7j = 3(2j + 5) + 1

Combine like terms: 11j + -7j = 4j
22 + 4j = 3(2j + 5) + 1

Reorder the terms:
22 + 4j = 3(5 + 2j) + 1
22 + 4j = (5 * 3 + 2j * 3) + 1
22 + 4j = (15 + 6j) + 1

Reorder the terms:
22 + 4j = 15 + 1 + 6j

Combine like terms: 15 + 1 = 16
22 + 4j = 16 + 6j

Solving
22 + 4j = 16 + 6j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-6j' to each side of the equation.
22 + 4j + -6j = 16 + 6j + -6j

Combine like terms: 4j + -6j = -2j
22 + -2j = 16 + 6j + -6j

Combine like terms: 6j + -6j = 0
22 + -2j = 16 + 0
22 + -2j = 16

Add '-22' to each side of the equation.
22 + -22 + -2j = 16 + -22

Combine like terms: 22 + -22 = 0
0 + -2j = 16 + -22
-2j = 16 + -22

Combine like terms: 16 + -22 = -6
-2j = -6

Divide each side by '-2'.
j = 3

Simplifying
j = 3

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