11(j-2)-6(2-j)+2(j-2)=0

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Solution for 11(j-2)-6(2-j)+2(j-2)=0 equation:


Simplifying
11(j + -2) + -6(2 + -1j) + 2(j + -2) = 0

Reorder the terms:
11(-2 + j) + -6(2 + -1j) + 2(j + -2) = 0
(-2 * 11 + j * 11) + -6(2 + -1j) + 2(j + -2) = 0
(-22 + 11j) + -6(2 + -1j) + 2(j + -2) = 0
-22 + 11j + (2 * -6 + -1j * -6) + 2(j + -2) = 0
-22 + 11j + (-12 + 6j) + 2(j + -2) = 0

Reorder the terms:
-22 + 11j + -12 + 6j + 2(-2 + j) = 0
-22 + 11j + -12 + 6j + (-2 * 2 + j * 2) = 0
-22 + 11j + -12 + 6j + (-4 + 2j) = 0

Reorder the terms:
-22 + -12 + -4 + 11j + 6j + 2j = 0

Combine like terms: -22 + -12 = -34
-34 + -4 + 11j + 6j + 2j = 0

Combine like terms: -34 + -4 = -38
-38 + 11j + 6j + 2j = 0

Combine like terms: 11j + 6j = 17j
-38 + 17j + 2j = 0

Combine like terms: 17j + 2j = 19j
-38 + 19j = 0

Solving
-38 + 19j = 0

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '38' to each side of the equation.
-38 + 38 + 19j = 0 + 38

Combine like terms: -38 + 38 = 0
0 + 19j = 0 + 38
19j = 0 + 38

Combine like terms: 0 + 38 = 38
19j = 38

Divide each side by '19'.
j = 2

Simplifying
j = 2

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